The finale of Lucasfilm’s Obi-Wan Kenobi Limited Run series saw a cameo from Qui-Gon Jinn actor Liam Neeson. After claiming that he would never return for a Star Wars TV show, it turns out the actor was telling just a little bit of a fib.
Why did Liam Neeson return for Obi-Wan Kenobi?
After five episodes of teasing, the beloved Jedi master Qui-Gon Jinn made an appearance during the finale of Obi-Wan Kenobi. Played, once again, by Liam Neeson, the character’s cameo was a long-awaited moment for fans everywhere.
Following the episode’s premiere, Neeson engaged in an interview with The Hollywood Reporter. Discussing his return to Star Wars, the actor revealed that he would not want anyone else playing his character.
Furthermore, Liam Neeson explained that he has a great respect for George Lucas and the prequel trilogy. As such, he felt obligated to return to the franchise, even if just for a bit.
“I certainly didn’t want anyone else playing Qui-Gon Jinn, and I wanted to show my respect for George [Lucas] and that mythical world that he created,” Neeson explained. “Plus, Ewan [McGregor] is a pal, and I loved working with him during The Phantom Menace 25 years ago.”
Will Qui-Gon Jinn be in Obi-Wan Kenobi Season 2?
Qui-Gon Jinn’s appearance in the finale of Obi-Wan Kenobi does lead the door open for more appearances in the future. But should that door be closed already?
Lucasfilm, Ewan McGregor and others have expressed interest in a second season, or story, for Obi-Wan. With the series being one of the most popular pieces of Disney Plus content yet, it makes sense that they’d want to continue.
If a second season does end up taking place after this season, then Qui-Gon Jinn could make an appearance again. After all, Kenobi and Jinn have a lot of training to do in order for the former to gain his Force Ghost powers.
On the other hand, maybe it’s best to not have another season of the show. As good as it was, it’s sometimes best to let things end on a good note. There are a tonne of other Star Wars shows out there anyways.